ASKudah try berulang masih salah mohon bantuanny...

Hand Excel 5:23pm Jul 1 ASK udah try berulang masih salah mohon bantuannya kira" salahnya dimana ya? form upload: <?php include('connect.php'); $query = "SELECT * FROM relawan"; $result=mysql_query($query); echo " <form enctype='multipart/form-data' method='POST' action='?p=frel'> <label> <select name='relawan'> <option value=0> Nama relawan </option>"; while($row=mysql_fetch_array($result)){ echo "<option value='$row[1]'>$row[1]</option>"; } echo "</select> </label> <label> <input name='picture' type='FILE' /> </label> <label> <input type='submit' value='Upload' /> </label> </form>"; ?> form action: <?php include('connect.php'); $relawan=$_POST['relawan']; $name = $_FILES['picture']['name']; $size = $_FILES['picture']['size']; $error = $_FILES['picture']['error']; $uploaddir='./foto/'; $lokasi=$uploaddir.$name; if($size > 0 || $error == 0){ $move = move_uploaded_file($_FILES['picture']['tmp_name'],$lokasi); if($move){ echo "File Berhasil diupload"; mysql_query("insert into foto values('','$relawan','$name','foto/$name')"); }else{ echo "Gagal mengupload file"; } }else{ echo "Gagal mengupload file: ".$error; } ?>

Hand Excel 02 Jul, 2013

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Source: http://www.facebook.com/groups/35688476100/?id=10151729391511101
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