Senin, 01 Juli 2013

ASKudah try berulang masih salah mohon bantuanny...

Hand Excel 5:23pm Jul 1
ASK

udah try berulang masih salah mohon bantuannya kira" salahnya dimana ya?

form upload:
<?php
include('connect.php');
$query = "SELECT * FROM relawan";
$result=mysql_query($query);
echo "
<form enctype='multipart/form-data' method='POST' action='?p=frel'>
<label>
<select name='relawan'>
<option value=0> Nama relawan </option>";
while($row=mysql_fetch_array($result)){
echo "<option value='$row[1]'>$row[1]</option>";
}
echo "</select>
</label>
<label>
<input name='picture' type='FILE' />
</label>
<label>
<input type='submit' value='Upload' />
</label>
</form>";
?>

form action:
<?php
include('connect.php');

$relawan=$_POST['relawan'];
$name = $_FILES['picture']['name'];
$size = $_FILES['picture']['size'];
$error = $_FILES['picture']['error'];
$uploaddir='./foto/';
$lokasi=$uploaddir.$name;
if($size > 0 || $error == 0){
$move = move_uploaded_file($_FILES['picture']['tmp_name'],$lokasi);
if($move){
echo "File Berhasil diupload";
mysql_query("insert into foto values('','$relawan','$name','foto/$name')");
}else{
echo "Gagal mengupload file";
}
}else{
echo "Gagal mengupload file: ".$error;
}
?>

Hand Excel 02 Jul, 2013


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Source: http://www.facebook.com/groups/35688476100/?id=10151729391511101
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