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gan ada yang mw ditanyane, saya ingn menampilakn d... Aug 30th 2013, 08:30, by Sadewa Saputra | gan ada yang mw ditanyane, saya ingn menampilakn data detail pinjam $tampil = mysql_query("select * from detail_pinjam where no_pinjam='$no'") or die (mysql_error()); while($data=mysql_fetch_array($tampil)){ $ulang = $data['kode_barang']; } foreach($ulang as $key => $kode) { echo $key; } saya ingin kode_barang dan jumlah di for sesuai data data yang ada table detail pinjam dengan clause no_pinjam mohon pencerahannya GAN ???? |
| | $ulang bukan array :( |
| | ok saya udh ditambahin array dengan kode [] tapi di sintax $tampil = mysql_query("select * from detail_pinjam where no_pinjam='$no'") or die (mysql_error( )); while($data=mysql_fetch_array($tampil)){ $ulang[] = $data['kode_barang']; $jml[] = $data['kode_barang']; } foreach($ulang as $key => $kode) { echo $kode; }
gimana cara menampilakn array dari jumlah,, mohon bantuannya Gunawan Mujur Wibisono | | |
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