bingung saya kenapa ini kode gagal terus melakukan update padhal di program lainya work sedangkan di progam yang satu ini ko ga work kenapa ya? mohn bantuanya master
<?php
include("../config.php");
$id_kat =$_GET['id_kat'];
$query ="select * from kategori where id_kat='$id_kat'";
$result =mysql_query($query) or die("gagal melakukan query");
$buff = mysql_fetch_array($result);
mysql_close();
?>
<?php
include("../config.php");
if (isset($_POST['update'])) {
$kategori= $_POST['kategori'];
$id_kat = $_POST['id_kat'];
$query = mysql_query("update kategori set kategori='$kategori' where id_kat='$id_kat'");
if ($query){
echo"<script>alert('Data Berhasil Diupdate ')
location.replace('?page=tampil_kategori')</script>";
} else
echo "<script>alert('Data Gagal Diupdate ')
location.replace('?page=tampil_kategori')</script>";
}
?>
<html>
<head>
<style type="text/css">
<!--
.style1 {
color: #FFFFFF;
font-weight: bold;
}
.style2 {color: #000000}
input{border-radius:3px;
font-size:15px;
height:28px;
}
textarea{border-radius:3px;}
input:focus{
outline: none;
-moz-box-shadow:0px 0px 5px #20f;
-webkit-box-shadow:0px 0px 5px #20f;
box-shadow:0px 0px 5px #20f;
}
textarea:focus{
outline: none;
-moz-box-shadow:0px 0px 5px #20f;
-webkit-box-shadow:0px 0px 5px #20f;
box-shadow:0px 0px 5px #20f;
border-radius:2px;
}
-->
</style>
</head>
<body>
<FORM ACTION="" METHOD="POST" NAME="input">
<table width="330" border="0" align="center" cellpadding="1" cellspacing="1" bordercolor="#000000" bgcolor="#FFFFFF">
<tr valign="" bgcolor="#CCCCCC">
<td colspan="2"><div align="center" class="style1 style2">
<p>Update Kategori </p>
</div></td>
</tr>
<tr>
<td width="88" height="28"><strong>kategori</strong></td>
<td width="251">
<input type="text" name="kategori" size="30"value="<?php echo $buff['kategori']; ?>"></td>
</tr>
<input type="hidden" name="id_kat" value="<? echo $id_kat; ?>"/>
<tr>
<td> </td>
<td>
</td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="update" value="Update"></td>
</tr>
</table>
</FORM>
</div>
</body>
</html>
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