PHP Indonesia - Facebook: Mohon Bantuan Adakah yg salah dengan script ini : ...

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Mohon Bantuan Adakah yg salah dengan script ini : ... Sep 20th 2013, 08:45, by Iwan Al Haris Iwan Al Haris 8:45am Sep 20 Mohon Bantuan Adakah yg salah dengan script ini : $output = mysql_query("select * from data"); while($data=mysql_fetch_row($output)) { $ou = mysql_query("select * from data2 where nama_barang = '$data[0]'"); $vva1 = mysql_result($ou,0,'jml_data'); } Hasilnya : Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index Tetapi kalau $data[0] tk ganti angka itu ndak ada masalah Cahya Dsn 9:02am Sep 20 "...kalau $data[0] tk ganti angka itu ndak ada masalah.." ... "tk" maksudnya? ... maklum gan ane masih nubi, kalo bahasa sepotong-sepotong (disingkat) suka tulalit, tidak tahu maksudnya.. ^_^V Iwan Al Haris 9:04am Sep 20 pada scrpit : $ou = mysql_query("select * from data2 where nama_barang = '$data[0]'"); kalau $data[0] saya gnti nilai misal '100', itu error nya hilang :) Fuad Ainun Najib 9:07am Sep 20 sory gan, ane bingung $data[0](isi dan maksudnya apa) dan $data(mysql_fetch_...) ?? Cahya Dsn 9:07am Sep 20 kalo dijadiin: $ou = mysql_query("select * from data2 where nama_barang = '{$data[0]}' "); masih error juga? Iwan Al Haris 9:11am Sep 20 Fuad Ainun Najib dari script itu kalau di jalankan muncul error, tp klo variabel $data[0] itu saya gnti angka misal 100, itu error nya hilang Cahya Dsn Masih error gan, maaf sya juga nubi jg :) Cahya Dsn 9:15am Sep 20 //.. $output = mysql_query("select * from data"); while($data=mysql_fetch_array($output)) { if($ou = mysql_query("select * from data2 where nama_barang = '{$data[0]}' ")) { $vva1 = mysql_result($ou,0,'jml_data'); } } //.. kalo gini errornya apa? Fuad Ainun Najib 9:18am Sep 20 maksud saya isi dari $data[0] itu apa (contoh : $data[0]=100) ??? Iwan Al Haris 9:19am Sep 20 itu kan nilai yg diambil dari : $output = mysql_query("select * from data"); while($data=mysql_fetch_row($output)) Iwan Al Haris 9:21am Sep 20 Cahya Dsn : Error gan, Parse error: syntax error, unexpected '{' in

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