| <tr> <td><strong>Nama</strong></td> <td>:</td> <td><?php echo $x['nama']; ?></td> </tr> A PHP Error was encountered
Severity: Notice
Message: Undefined index: nama
Filename: views/kartu.php
Line Number: 13 (yg 'nama') harusnya gimana? dilangsungin $nama kah? |
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| array result() nya mana? |
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| contohin :v |
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| code nya yg lengkap kakak. segitu ndak kelihatan masalahnya |
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| msalah'a tu apa?? coding'a sis... |
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| post aja kode yang lengkap |
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| kurang lengkap |
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| <?php foreach($data->result() as $key=>$t): ?>
<?php for($x=1;$x<=31;$x++){ ?> <?php $c="cuti".$x; ?> <?php $s="sakit".$x; ?> <?php $iz="izin".$x; ?>
<td class=" <?php if( $t->$c != 0){ echo "cuti";} ?> <?php if( $sakit[$key]->$s != 0){ echo "sakit";} ?> <?php if( $izin[$key]->$iz != 0){ echo "izin";} ?> "> </td> <?php } ?>
<?php endforeach ?> CONTOH |
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| <body> <table width="305" height="268" border="1,5" align="center" bgcolor="#666666"> <tr> <td width="317"><table width="297" height="102" border="0"> <tr> <td width="114"><strong>Kode Anggota</strong> </td> <td width="10">:</td> <td width="159"><?php echo $kode_anggota ?></td> </tr> <tr> <td><strong>Nama</strong></td> <td>:</td> <td><?php echo $x['nama']; ?></td> </tr> <tr> <td><strong>Alamat</strong></td> <td>:</td> <td><?php echo $x['alamat']; ?></td> </tr> <tr> <td><strong>Telephone</strong></td> <td>:</td> <td><?php echo $x['tlp'];?></td> </tr> </table> <table width="297" height="51" border="0"> <tr> <td width="291" align="center"><img src="<?php echo base_url() ?>fotos/<?php echo $x['foto'] ?>" width="117" height="100" border="1"/></td> </tr> </table> <table width="297" height="52" border="0"> <tr> <td width="114"><strong>Aktif</strong></td> <td width="11">:</td> <td width="158"><?php echo $tanggal;?></td> </tr> <tr> <td><strong>Berlaku </strong></td> <td>:</td> <td><?php echo $tanggal_akhir;?></td> </tr> </table> </td> </tr> </table>
</body> <p align="center"><a href="#" onclick=print();>Print</a> setiap echonya eror.... |
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| $x[] datang dari mana? |
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| query'a mn mbak?? |
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| include file nya mungkin........ |
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| coba var_dump($x); liat apa yang terjadi |
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| hasil query diatas |
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| Variable x belum dideklarasikan tuh. kode_anggota juga. Harusnya ada 1 script PHP di atas tabel itu. |
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| harusnya apa? maaf baru bljr |
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| scrip buat query database nya kakak |
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| sik bentar... apakah kakak pake framework?? CI??? |
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| syntax query nya mana yah mbak ? yang gitu masalahnya di query mbak . contoh : $sql = "SELECT * FROM artikel"; $hsl = mysql_query($sql); while ($hasil = mysql_fetch_array($hsl)) { // nah di sini baru masukin syntax yang tadi mbak post . // contoh : $nama = $hasil['nama']; } |
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| gini bukan? <tr> <td>NIS</td> <td><input name="nis" type="text" id="nis" value="<?php echo set_value('nis');?>"></td> </tr>
aduh ga ngerti :( |
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| oh querynya disimpen sebelum yg itu gitu? |
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| iyah . coba liat di sini deh . https://planetprogramming.wordpress.com/2013/07/23/menampilkan-data-dari-database-dengan-php/ |
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| iya pake CI. oke diliat dulu |
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| owalah. ndak bilang dari tadi... masalah di modelnya... coba copas controler c_pendaftaran function buat_kartu |
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| gini? <tr> <td><strong>Nama</strong></td> <td>:</td> <td><?php $sql = "SELECT * FROM kartu"; $hsl = mysql_query($sql); while ($hasil = mysql_fetch_array($hsl)) {$nama=$hasil ['nama'];} ?></td> </tr> tapi malah eror di {$nama=$hasil ['nama'];} ?></td> |
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| while ($hasil = mysql_fetch_array($hsl)); $nama=$hasil ['nama']; ?> |
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