PHP Indonesia - Facebook: Ini knpa yaa ?? apa yang salah

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Ini knpa yaa ?? apa yang salah Oct 27th 2013, 06:33, by Puput Meylana Agustine Puput Meylana Agustine 6:33am Oct 27 Ini knpa yaa ?? apa yang salah Alnova Syafithra 6:34am Oct 27 coba di lihat line 41 itu apa ? Pengaturan Privasi 6:35am Oct 27 Undefine index jelas menunjukkan akan adanya suatu peringatan,,, Angga Rizky 6:37am Oct 27 di database sudah tersedia unser dan password belom Puput Meylana Agustine 6:38am Oct 27 di line 41 ini if($password==$baris['password']&& terus di databasenya udh dikash usernm n password Gunawan Mujur Wibisono 6:39am Oct 27 $password udah ditentukan dari $_POST ?? Puput Meylana Agustine 6:40am Oct 27 pi aku pkk post kok Fery Putra Tarigan Sibero 6:42am Oct 27 kalo seperti ini variable $baris harus di assign value dari $_POST, dan field input dengan name='password' harus terjadi ketika di submit Fery Putra Tarigan Sibero 6:43am Oct 27 biar gampang ganti aja dengan $_REQUEST itu mencakup $_POST sama $_GET Surya Ramsey 6:44am Oct 27 $username = $_POST["username"]; $password = $_POST["password"]; $sql="select * from t_user where username=$username and password=$password"; terus di cek num_row nya if >0 then true.. hmmm kepanjangan, CMIIW Gunawan Mujur Wibisono 6:45am Oct 27 share script km Puput Meylana Agustine 6:48am Oct 27 ini script ku .... <?php session_start(); ?> <fieldset class="field"> <legend>Form Login</legend> <form method="post" action="?hal=login&aksi=login"> <table> <tr> <td>Username</td> <td>:</td> <td><input type="text" name="username"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input type="text" name="password"></td> </tr> <tr> <td colspan="3"> <input type="submit" name="Login" value="Login"> <input type="reset" name="Can" value="Cancel"> </tr> </table> </form> </fieldset> <?php if($aksi=='login'){ $username=$_POST['username']; $password=$_POST['password']; if(isset($_POST['Login'])){ $query="select*from admin where username='$username' and password='$password'"; $hasil=mysql_query($query) or die(mysql_error()); $baris=mysql_fetch_array($hasil); if($password==$baris['password'] && $username==$baris['username']){ ?> <script> alert('Login Sukses'); location.href="admin/index.php"; </script> <?php $_SESSION['username']=$baris['username']; $_SESSION['password']=$baris['password']; header('location:admin/index.php'); } ?> } else { ?> <script> alert('Login Gagal') location.href="?hal=login"; </script> <?php } } ?> Gunawan Mujur Wibisono 6:50am Oct 27 ??? >>if($aksi=='login'){ $aksi dari mana?? Puput Meylana Agustine 6:53am Oct 27 tnya paak gruku Gunawan Mujur Wibisono 6:54am Oct 27 ooo rumput bergoyang krn $aksi tak di deklarasikan.. maka didalamnya gk di proses trus lanjut ke akhir Surya Ramsey 6:55am Oct 27 hmmm $aksi itu dari mna?? :D Puput Meylana Agustine 6:55am Oct 27 seharusnya gmn ??? Suryo Prasetyo 6:58am Oct 27 $aksi = $_GET['aksi']; baru if($aksi=='login') Surya Ramsey 6:58am Oct 27 $baris= mysql_num_row($hasil); if($hasil>0){ ?><script> alert('Login Sukses'); location.href="admin/index.php"; </script> <?php $_SESSION['username']=$baris['username']; $_SESSION['password']=$baris['password']; header('location:admin/index.php'); }else{ ?><script> alert('Login Gagal') location.href="?hal=login"; </script> Gunawan Mujur Wibisono 7:00am Oct 27 ?> } //if(isset($_POST['Login'])) else { ?> salah Fery Putra Tarigan Sibero 7:14am Oct 27 itu mungkin maksudnya $_GET['aksi']=='login', tapi kalo register globalnya PHP di aktifkan bisa langsung $aksi, cuman itu rentan terhadap SQL injection.

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